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45553414403 = 7229123722973
BaseRepresentation
bin101010011011001100…
…011111000100000011
311100120200210012220102
4222123030133010003
51221243133230103
632532115433015
73201566430230
oct523314370403
9140520705812
1045553414403
1118356795522
1289b38b576b
1343ac7787a3
1422c1d6a787
1512b9307e88
hexa9b31f103

45553414403 has 16 divisors (see below), whose sum is σ = 52332934080. Its totient is φ = 38842160256.

The previous prime is 45553414399. The next prime is 45553414427. The reversal of 45553414403 is 30441435554.

It is a cyclic number.

It is not a de Polignac number, because 45553414403 - 22 = 45553414399 is a prime.

It is a super-2 number, since 2×455534144032 (a number of 22 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (45553414453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1971425 + ... + 1994397.

It is an arithmetic number, because the mean of its divisors is an integer number (3270808380).

Almost surely, 245553414403 is an apocalyptic number.

45553414403 is a deficient number, since it is larger than the sum of its proper divisors (6779519677).

45553414403 is a wasteful number, since it uses less digits than its factorization.

45553414403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24446.

The product of its (nonzero) digits is 288000, while the sum is 38.

Adding to 45553414403 its reverse (30441435554), we get a palindrome (75994849957).

The spelling of 45553414403 in words is "forty-five billion, five hundred fifty-three million, four hundred fourteen thousand, four hundred three".

Divisors: 1 7 229 1237 1603 8659 22973 160811 283273 1982911 5260817 28417601 36825719 198923207 6507630629 45553414403