Base | Representation |
---|---|
bin | 10101001001011100101100… |
… | …11011111110010000111001 |
3 | 20002122202022010002100200020 |
4 | 22210232112123332100321 |
5 | 22043410432004012423 |
6 | 242523412110201053 |
7 | 12536545545643623 |
oct | 1244562633762071 |
9 | 202582263070606 |
10 | 46504134829113 |
11 | 138aa324829265 |
12 | 52709907b3189 |
13 | 1cc44235b3570 |
14 | b6ab526dbc13 |
15 | 559a2c7e24e3 |
hex | 2a4b966fe439 |
46504134829113 has 32 divisors (see below), whose sum is σ = 70704649314432. Its totient is φ = 26933938560000.
The previous prime is 46504134829093. The next prime is 46504134829127. The reversal of 46504134829113 is 31192843140564.
It is not a de Polignac number, because 46504134829113 - 220 = 46504133780537 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (51).
It is not an unprimeable number, because it can be changed into a prime (46504134829153) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 30890538 + ... + 32360988.
It is an arithmetic number, because the mean of its divisors is an integer number (2209520291076).
Almost surely, 246504134829113 is an apocalyptic number.
It is an amenable number.
46504134829113 is a deficient number, since it is larger than the sum of its proper divisors (24200514485319).
46504134829113 is a wasteful number, since it uses less digits than its factorization.
46504134829113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1518185.
The product of its (nonzero) digits is 2488320, while the sum is 51.
Adding to 46504134829113 its reverse (31192843140564), we get a palindrome (77696977969677).
The spelling of 46504134829113 in words is "forty-six trillion, five hundred four billion, one hundred thirty-four million, eight hundred twenty-nine thousand, one hundred thirteen".
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