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471117101417 = 1309935965883
BaseRepresentation
bin1101101101100001100…
…01000111100101101001
31200001000221221102220222
412312300301013211221
530204321434221132
61000232254255425
746015502201054
oct6666061074551
91601027842828
10471117101417
1117188835a286
12773801b7575
1335570343641
1418b332c9a9b
15c3c511c412
hex6db0c47969

471117101417 has 4 divisors (see below), whose sum is σ = 471153080400. Its totient is φ = 471081122436.

The previous prime is 471117101401. The next prime is 471117101419. The reversal of 471117101417 is 714101711174.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 714101711174 = 2357050855587.

It is a cyclic number.

It is not a de Polignac number, because 471117101417 - 24 = 471117101401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (471117101419) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17969843 + ... + 17996040.

It is an arithmetic number, because the mean of its divisors is an integer number (117788270100).

Almost surely, 2471117101417 is an apocalyptic number.

It is an amenable number.

471117101417 is a deficient number, since it is larger than the sum of its proper divisors (35978983).

471117101417 is a wasteful number, since it uses less digits than its factorization.

471117101417 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 35978982.

The product of its (nonzero) digits is 5488, while the sum is 35.

The spelling of 471117101417 in words is "four hundred seventy-one billion, one hundred seventeen million, one hundred one thousand, four hundred seventeen".

Divisors: 1 13099 35965883 471117101417