Base | Representation |
---|---|
bin | 100010010001111100000… |
… | …1100110100110100010111 |
3 | 121200102001221010101002001 |
4 | 1010203320030310310113 |
5 | 1104143021224034210 |
6 | 14004224235300131 |
7 | 664251036336334 |
oct | 104437014646427 |
9 | 17612057111061 |
10 | 4711448268055 |
11 | 15571287a1521 |
12 | 64113a5aa647 |
13 | 282398001589 |
14 | 12406cc8198b |
15 | 8285014c03a |
hex | 448f8334d17 |
4711448268055 has 16 divisors (see below), whose sum is σ = 5685634684800. Its totient is φ = 3747896415520.
The previous prime is 4711448268053. The next prime is 4711448268071. The reversal of 4711448268055 is 5508628441174.
It is not a de Polignac number, because 4711448268055 - 21 = 4711448268053 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4711448267987 and 4711448268005.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4711448268053) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17381556 + ... + 17650534.
It is an arithmetic number, because the mean of its divisors is an integer number (355352167800).
Almost surely, 24711448268055 is an apocalyptic number.
4711448268055 is a deficient number, since it is larger than the sum of its proper divisors (974186416745).
4711448268055 is a wasteful number, since it uses less digits than its factorization.
4711448268055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 288734.
The product of its (nonzero) digits is 8601600, while the sum is 55.
The spelling of 4711448268055 in words is "four trillion, seven hundred eleven billion, four hundred forty-eight million, two hundred sixty-eight thousand, fifty-five".
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