Base | Representation |
---|---|
bin | 10101011100000110111101… |
… | …01010011101101101101011 |
3 | 20011221001020210021211220212 |
4 | 22232003132222131231223 |
5 | 22134412031424331403 |
6 | 244134130022411335 |
7 | 12634064255024663 |
oct | 1256033652355553 |
9 | 204831223254825 |
10 | 47145296714603 |
11 | 14027231a1363a |
12 | 53550a8590b4b |
13 | 203ca22c31219 |
14 | b8dbb759b1a3 |
15 | 56b5561544d8 |
hex | 2ae0dea9db6b |
47145296714603 has 4 divisors (see below), whose sum is σ = 47211792197280. Its totient is φ = 47078801231928.
The previous prime is 47145296714597. The next prime is 47145296714693. The reversal of 47145296714603 is 30641769254174.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 47145296714603 - 212 = 47145296710507 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (47145296714693) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33247740275 + ... + 33247741692.
It is an arithmetic number, because the mean of its divisors is an integer number (11802948049320).
Almost surely, 247145296714603 is an apocalyptic number.
47145296714603 is a deficient number, since it is larger than the sum of its proper divisors (66495482677).
47145296714603 is an equidigital number, since it uses as much as digits as its factorization.
47145296714603 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 66495482676.
The product of its (nonzero) digits is 30481920, while the sum is 59.
The spelling of 47145296714603 in words is "forty-seven trillion, one hundred forty-five billion, two hundred ninety-six million, seven hundred fourteen thousand, six hundred three".
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