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47145296714597 is a prime number
BaseRepresentation
bin10101011100000110111101…
…01010011101101101100101
320011221001020210021211220122
422232003132222131231211
522134412031424331342
6244134130022411325
712634064255024654
oct1256033652355545
9204831223254818
1047145296714597
1114027231a13634
1253550a8590b45
13203ca22c31213
14b8dbb759b19b
1556b5561544d2
hex2ae0dea9db65

47145296714597 has 2 divisors, whose sum is σ = 47145296714598. Its totient is φ = 47145296714596.

The previous prime is 47145296714569. The next prime is 47145296714693. The reversal of 47145296714597 is 79541769254174.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 24256353905476 + 22888942809121 = 4925074^2 + 4784239^2 .

It is a cyclic number.

It is not a de Polignac number, because 47145296714597 - 218 = 47145296452453 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 47145296714597.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (47145296710597) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23572648357298 + 23572648357299.

It is an arithmetic number, because the mean of its divisors is an integer number (23572648357299).

Almost surely, 247145296714597 is an apocalyptic number.

It is an amenable number.

47145296714597 is a deficient number, since it is larger than the sum of its proper divisors (1).

47145296714597 is an equidigital number, since it uses as much as digits as its factorization.

47145296714597 is an evil number, because the sum of its binary digits is even.

The product of its digits is 533433600, while the sum is 71.

The spelling of 47145296714597 in words is "forty-seven trillion, one hundred forty-five billion, two hundred ninety-six million, seven hundred fourteen thousand, five hundred ninety-seven".