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47305113 = 328975443
BaseRepresentation
bin1011010001110…
…1000110011001
310022000100102020
42310131012121
544102230423
64405525053
71113041532
oct264350631
9108010366
1047305113
1124780039
1213a13789
139a538bb
1463d5689
1542464e3
hex2d1d199

47305113 has 8 divisors (see below), whose sum is σ = 63106848. Its totient is φ = 31520064.

The previous prime is 47305109. The next prime is 47305133. The reversal of 47305113 is 31150374.

47305113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 47305113 - 22 = 47305109 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (47305133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5970 + ... + 11412.

It is an arithmetic number, because the mean of its divisors is an integer number (7888356).

Almost surely, 247305113 is an apocalyptic number.

It is an amenable number.

47305113 is a deficient number, since it is larger than the sum of its proper divisors (15801735).

47305113 is a wasteful number, since it uses less digits than its factorization.

47305113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8343.

The product of its (nonzero) digits is 1260, while the sum is 24.

The square root of 47305113 is about 6877.8712549742. The cubic root of 47305113 is about 361.6618460380.

Adding to 47305113 its reverse (31150374), we get a palindrome (78455487).

The spelling of 47305113 in words is "forty-seven million, three hundred five thousand, one hundred thirteen".

Divisors: 1 3 2897 5443 8691 16329 15768371 47305113