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473481035238007 = 570816182948087
BaseRepresentation
bin110101110101000001110010…
…0111010011100101001110111
32022002110100022102211010221201
41223222003210322130221313
5444030003130010104012
64355002103524353331
7201505606304621626
oct15352034472345167
92262410272733851
10473481035238007
111279581a7848575
124512b968845847
13174270bab51b54
1484cc8665c56bd
1539b14dd072857
hex1aea0e4e9ca77

473481035238007 has 4 divisors (see below), whose sum is σ = 473481123894256. Its totient is φ = 473480946581760.

The previous prime is 473481035237983. The next prime is 473481035238011. The reversal of 473481035238007 is 700832530184374.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 473481035238007 - 231 = 473478887754359 is a prime.

It is a super-2 number, since 2×4734810352380072 (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (473481035233007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35765883 + ... + 47182204.

It is an arithmetic number, because the mean of its divisors is an integer number (118370280973564).

Almost surely, 2473481035238007 is an apocalyptic number.

473481035238007 is a deficient number, since it is larger than the sum of its proper divisors (88656249).

473481035238007 is an equidigital number, since it uses as much as digits as its factorization.

473481035238007 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 88656248.

The product of its (nonzero) digits is 13547520, while the sum is 55.

The spelling of 473481035238007 in words is "four hundred seventy-three trillion, four hundred eighty-one billion, thirty-five million, two hundred thirty-eight thousand, seven".

Divisors: 1 5708161 82948087 473481035238007