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47433343800113 = 411156910824393
BaseRepresentation
bin10101100100011111011111…
…00110111001001100110001
320012221120202021200220111022
422302033233212321030301
522204121442003100423
6244514324411225225
712663642322612205
oct1262175746711461
9205846667626438
1047433343800113
1114128405a99307
1253a0a96a48215
132060c395a2c5b
14b9db0105ab05
15573cb4293dc8
hex2b23ef9b9331

47433343800113 has 4 divisors (see below), whose sum is σ = 48590254624548. Its totient is φ = 46276432975680.

The previous prime is 47433343800077. The next prime is 47433343800131. The reversal of 47433343800113 is 31100834333474.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 582700169104 + 46850643631009 = 763348^2 + 6844753^2 .

It is a cyclic number.

It is not a de Polignac number, because 47433343800113 - 210 = 47433343799089 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (47433343800413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 578455412156 + ... + 578455412237.

It is an arithmetic number, because the mean of its divisors is an integer number (12147563656137).

Almost surely, 247433343800113 is an apocalyptic number.

It is an amenable number.

47433343800113 is a deficient number, since it is larger than the sum of its proper divisors (1156910824435).

47433343800113 is a wasteful number, since it uses less digits than its factorization.

47433343800113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1156910824434.

The product of its (nonzero) digits is 870912, while the sum is 44.

The spelling of 47433343800113 in words is "forty-seven trillion, four hundred thirty-three billion, three hundred forty-three million, eight hundred thousand, one hundred thirteen".

Divisors: 1 41 1156910824393 47433343800113