4773011106343 has 4 divisors (see below), whose sum is σ = 4781142301320. Its totient is φ = 4764879911368.

The previous prime is 4773011106323. The next prime is 4773011106373. The reversal of 4773011106343 is 3436011103774.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4773011106343 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4773011106296 and 4773011106305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4773011106323) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4065596608 + ... + 4065597781.

It is an arithmetic number, because the mean of its divisors is an integer number (1195285575330).

Almost surely, 2^{4773011106343} is an apocalyptic number.

4773011106343 is a deficient number, since it is larger than the sum of its proper divisors (8131194977).

4773011106343 is an equidigital number, since it uses as much as digits as its factorization.

4773011106343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8131194976.

The product of its (nonzero) digits is 127008, while the sum is 40.

The spelling of 4773011106343 in words is "four trillion, seven hundred seventy-three billion, eleven million, one hundred six thousand, three hundred forty-three".