Base | Representation |
---|---|
bin | 101100101000100101… |
… | …110101111011011001 |
3 | 11120201000120020011020 |
4 | 230220211311323121 |
5 | 1241122431232423 |
6 | 34003340553053 |
7 | 3314433203346 |
oct | 545045657331 |
9 | 146630506136 |
10 | 47925649113 |
11 | 19363863581 |
12 | 9356252789 |
13 | 469a092674 |
14 | 246903d7cd |
15 | 13a76e74e3 |
hex | b28975ed9 |
47925649113 has 4 divisors (see below), whose sum is σ = 63900865488. Its totient is φ = 31950432740.
The previous prime is 47925649103. The next prime is 47925649207. The reversal of 47925649113 is 31194652974.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 47925649113 - 29 = 47925648601 is a prime.
It is not an unprimeable number, because it can be changed into a prime (47925649103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7987608183 + ... + 7987608188.
It is an arithmetic number, because the mean of its divisors is an integer number (15975216372).
Almost surely, 247925649113 is an apocalyptic number.
It is an amenable number.
47925649113 is a deficient number, since it is larger than the sum of its proper divisors (15975216375).
47925649113 is a wasteful number, since it uses less digits than its factorization.
47925649113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15975216374.
The product of its digits is 1632960, while the sum is 51.
The spelling of 47925649113 in words is "forty-seven billion, nine hundred twenty-five million, six hundred forty-nine thousand, one hundred thirteen".
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