Base | Representation |
---|---|
bin | 10101110100111101001011… |
… | …10001101111110001011011 |
3 | 20021221122220200102201120201 |
4 | 22322132211301233301123 |
5 | 22242404013422023141 |
6 | 250030242133403031 |
7 | 13052546656110646 |
oct | 1272364561576133 |
9 | 207848820381521 |
10 | 47999040814171 |
11 | 14326308230847 |
12 | 5472651799477 |
13 | 20a23a0541a35 |
14 | bbd2475d2a5d |
15 | 583872864031 |
hex | 2ba7a5c6fc5b |
47999040814171 has 4 divisors (see below), whose sum is σ = 50525306120200. Its totient is φ = 45472775508144.
The previous prime is 47999040814159. The next prime is 47999040814177. The reversal of 47999040814171 is 17141804099974.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 47999040814171 - 211 = 47999040812123 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (47999040814177) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1263132652986 + ... + 1263132653023.
It is an arithmetic number, because the mean of its divisors is an integer number (12631326530050).
Almost surely, 247999040814171 is an apocalyptic number.
47999040814171 is a deficient number, since it is larger than the sum of its proper divisors (2526265306029).
47999040814171 is a wasteful number, since it uses less digits than its factorization.
47999040814171 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2526265306028.
The product of its (nonzero) digits is 18289152, while the sum is 64.
The spelling of 47999040814171 in words is "forty-seven trillion, nine hundred ninety-nine billion, forty million, eight hundred fourteen thousand, one hundred seventy-one".
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