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48112074113 = 1972715232287
BaseRepresentation
bin101100110011101100…
…111111110110000001
311121012000100121011212
4230303230333312001
51242013142332423
634034040415505
73322155611435
oct546354776601
9147160317155
1048112074113
111944a014424
1293a8777595
1346c98a5b0c
142485aca9c5
1513b8c6e578
hexb33b3fd81

48112074113 has 16 divisors (see below), whose sum is σ = 50769438720. Its totient is φ = 45467387856.

The previous prime is 48112074091. The next prime is 48112074149. The reversal of 48112074113 is 31147021184.

It is a cyclic number.

It is not a de Polignac number, because 48112074113 - 214 = 48112057729 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 48112074113.

It is not an unprimeable number, because it can be changed into a prime (48112074013) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 21036056 + ... + 21038342.

It is an arithmetic number, because the mean of its divisors is an integer number (3173089920).

Almost surely, 248112074113 is an apocalyptic number.

It is an amenable number.

48112074113 is a deficient number, since it is larger than the sum of its proper divisors (2657364607).

48112074113 is a wasteful number, since it uses less digits than its factorization.

48112074113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4556.

The product of its (nonzero) digits is 5376, while the sum is 32.

Adding to 48112074113 its reverse (31147021184), we get a palindrome (79259095297).

The spelling of 48112074113 in words is "forty-eight billion, one hundred twelve million, seventy-four thousand, one hundred thirteen".

Divisors: 1 19 727 1523 2287 13813 28937 43453 1107221 1662649 3483101 21037199 31590331 66178919 2532214427 48112074113