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48124871493 = 316041623831
BaseRepresentation
bin101100110100011101…
…110100001101000101
311121012220102202212220
4230310131310031011
51242024431341433
634035215002553
73322402441536
oct546435641505
9147186382786
1048124871493
1119456265276
1293b0b09459
1346cc436a2a
14248769c68d
1513b9e4b2b3
hexb34774345

48124871493 has 4 divisors (see below), whose sum is σ = 64166495328. Its totient is φ = 32083247660.

The previous prime is 48124871471. The next prime is 48124871497. The reversal of 48124871493 is 39417842184.

48124871493 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 48124871493 - 213 = 48124863301 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (48124871497) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8020811913 + ... + 8020811918.

It is an arithmetic number, because the mean of its divisors is an integer number (16041623832).

Almost surely, 248124871493 is an apocalyptic number.

It is an amenable number.

48124871493 is a deficient number, since it is larger than the sum of its proper divisors (16041623835).

48124871493 is a wasteful number, since it uses less digits than its factorization.

48124871493 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16041623834.

The product of its digits is 1548288, while the sum is 51.

The spelling of 48124871493 in words is "forty-eight billion, one hundred twenty-four million, eight hundred seventy-one thousand, four hundred ninety-three".

Divisors: 1 3 16041623831 48124871493