48284952140283 has 4 divisors (see below), whose sum is σ = 64379936187048. Its totient is φ = 32189968093520.

The previous prime is 48284952140251. The next prime is 48284952140287. The reversal of 48284952140283 is 38204125948284.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 48284952140283 - 2⁵ = 48284952140251 is a prime.

It is a super-2 number, since 2×48284952140283² (a number of 28 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (48284952140287) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8047492023378 + ... + 8047492023383.

It is an arithmetic number, because the mean of its divisors is an integer number (16094984046762).

Almost surely, 2^{48284952140283} is an apocalyptic number.

48284952140283 is a deficient number, since it is larger than the sum of its proper divisors (16094984046765).

48284952140283 is a wasteful number, since it uses less digits than its factorization.

48284952140283 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16094984046764.

The product of its (nonzero) digits is 35389440, while the sum is 60.

The spelling of 48284952140283 in words is "forty-eight trillion, two hundred eighty-four billion, nine hundred fifty-two million, one hundred forty thousand, two hundred eighty-three".