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48305171843153 = 253728719038119
BaseRepresentation
bin10101111101110111011001…
…00110111100100001010001
320100000221002110222021222022
422332323230212330201101
522312412442442440103
6250423031204021225
713113635121656351
oct1276735446744121
9210027073867868
1048305171843153
1114434121212945
125501a48391815
1320c5209625334
14bcdda8ad0b61
1558b7dd3de138
hex2beeec9bc851

48305171843153 has 4 divisors (see below), whose sum is σ = 48305193418560. Its totient is φ = 48305150267748.

The previous prime is 48305171843143. The next prime is 48305171843167. The reversal of 48305171843153 is 35134817150384.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-48305171843153 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 48305171843095 and 48305171843104.

It is not an unprimeable number, because it can be changed into a prime (48305171843143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6981773 + ... + 12056346.

It is an arithmetic number, because the mean of its divisors is an integer number (12076298354640).

Almost surely, 248305171843153 is an apocalyptic number.

It is an amenable number.

48305171843153 is a deficient number, since it is larger than the sum of its proper divisors (21575407).

48305171843153 is a wasteful number, since it uses less digits than its factorization.

48305171843153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21575406.

The product of its (nonzero) digits is 4838400, while the sum is 53.

The spelling of 48305171843153 in words is "forty-eight trillion, three hundred five billion, one hundred seventy-one million, eight hundred forty-three thousand, one hundred fifty-three".

Divisors: 1 2537287 19038119 48305171843153