Search a number
-
+
48310457941 = 50819508061
BaseRepresentation
bin101100111111100001…
…110001011001010101
311121200211122112122001
4230333201301121111
51242414434123231
634105444435301
73330115055104
oct547741613125
9147624575561
1048310457941
1119540aa30a9
1294430a8b31
13472ba155b5
1424a41ac03b
1513cb3a9b61
hexb3f871655

48310457941 has 4 divisors (see below), whose sum is σ = 48319971084. Its totient is φ = 48300944800.

The previous prime is 48310457927. The next prime is 48310457959. The reversal of 48310457941 is 14975401384.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 15393613041 + 32916844900 = 124071^2 + 181430^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-48310457941 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 48310457891 and 48310457900.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (48310457971) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4748950 + ... + 4759111.

It is an arithmetic number, because the mean of its divisors is an integer number (12079992771).

Almost surely, 248310457941 is an apocalyptic number.

It is an amenable number.

48310457941 is a deficient number, since it is larger than the sum of its proper divisors (9513143).

48310457941 is an equidigital number, since it uses as much as digits as its factorization.

48310457941 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9513142.

The product of its (nonzero) digits is 483840, while the sum is 46.

The spelling of 48310457941 in words is "forty-eight billion, three hundred ten million, four hundred fifty-seven thousand, nine hundred forty-one".

Divisors: 1 5081 9508061 48310457941