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483112103 = 1728418359
BaseRepresentation
bin11100110010111…
…011010010100111
31020200001122012212
4130302323102213
51442134041403
6115534434035
714654246045
oct3462732247
91220048185
10483112103
11228782301
1211596291b
1379121366
144823b395
152c62e4d8
hex1ccbb4a7

483112103 has 4 divisors (see below), whose sum is σ = 511530480. Its totient is φ = 454693728.

The previous prime is 483112093. The next prime is 483112111. The reversal of 483112103 is 301211384.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-483112103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (483112193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14209163 + ... + 14209196.

It is an arithmetic number, because the mean of its divisors is an integer number (127882620).

Almost surely, 2483112103 is an apocalyptic number.

483112103 is a deficient number, since it is larger than the sum of its proper divisors (28418377).

483112103 is a wasteful number, since it uses less digits than its factorization.

483112103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28418376.

The product of its (nonzero) digits is 576, while the sum is 23.

The square root of 483112103 is about 21979.8112594262. The cubic root of 483112103 is about 784.6620331030.

Adding to 483112103 its reverse (301211384), we get a palindrome (784323487).

The spelling of 483112103 in words is "four hundred eighty-three million, one hundred twelve thousand, one hundred three".

Divisors: 1 17 28418359 483112103