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483125403 = 3213175571
BaseRepresentation
bin11100110010111…
…110100010011011
31020200002022110110
4130302332202123
51442140003103
6115535015403
714654332605
oct3462764233
91220068413
10483125403
112287912a2
1211596a563
1379127427
1448242175
152c633403
hex1ccbe89b

483125403 has 8 divisors (see below), whose sum is σ = 644478016. Its totient is φ = 321928200.

The previous prime is 483125389. The next prime is 483125417. The reversal of 483125403 is 304521384.

It is an interprime number because it is at equal distance from previous prime (483125389) and next prime (483125417).

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 483125403 - 25 = 483125371 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (483125473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 31393 + ... + 44178.

It is an arithmetic number, because the mean of its divisors is an integer number (80559752).

Almost surely, 2483125403 is an apocalyptic number.

483125403 is a deficient number, since it is larger than the sum of its proper divisors (161352613).

483125403 is a wasteful number, since it uses less digits than its factorization.

483125403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 77705.

The product of its (nonzero) digits is 11520, while the sum is 30.

The square root of 483125403 is about 21980.1138077126. The cubic root of 483125403 is about 784.6692335776.

Adding to 483125403 its reverse (304521384), we get a palindrome (787646787).

The spelling of 483125403 in words is "four hundred eighty-three million, one hundred twenty-five thousand, four hundred three".

Divisors: 1 3 2131 6393 75571 226713 161041801 483125403