Base | Representation |
---|---|
bin | 10101111110000110010000… |
… | …10110101000111101010101 |
3 | 20100001200200201220200002110 |
4 | 22333003020112220331111 |
5 | 22313030314300223131 |
6 | 250430431211101233 |
7 | 13114336661066514 |
oct | 1277031026507525 |
9 | 210050621820073 |
10 | 48313153523541 |
11 | 14437547708515 |
12 | 55034b5441819 |
13 | 20c5bac122b3a |
14 | bd0524b8a67b |
15 | 58bb08ebb646 |
hex | 2bf0c85a8f55 |
48313153523541 has 8 divisors (see below), whose sum is σ = 65042951022400. Its totient is φ = 31896062520192.
The previous prime is 48313153523533. The next prime is 48313153523651. The reversal of 48313153523541 is 14532535131384.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 48313153523541 - 23 = 48313153523533 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (48313153523501) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 78176623516 + ... + 78176624133.
It is an arithmetic number, because the mean of its divisors is an integer number (8130368877800).
Almost surely, 248313153523541 is an apocalyptic number.
It is an amenable number.
48313153523541 is a deficient number, since it is larger than the sum of its proper divisors (16729797498859).
48313153523541 is a wasteful number, since it uses less digits than its factorization.
48313153523541 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 156353247755.
The product of its digits is 2592000, while the sum is 48.
The spelling of 48313153523541 in words is "forty-eight trillion, three hundred thirteen billion, one hundred fifty-three million, five hundred twenty-three thousand, five hundred forty-one".
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