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483485332745451 = 3233691681448849
BaseRepresentation
bin110110111101110100011001…
…1100000110010110011101011
32100101212202011010120101201110
41231323220303200302303223
51001332410430140323301
64432142032352121403
7203560443155431401
oct15573506340626353
92311782133511643
10483485332745451
11130064a83997533
1246286843836263
13179a161843618a
148756b5a38d471
153ad686a4060d6
hex1b7ba33832ceb

483485332745451 has 8 divisors (see below), whose sum is σ = 647413836123600. Its totient is φ = 320940192265472.

The previous prime is 483485332745423. The next prime is 483485332745501. The reversal of 483485332745451 is 154547233584384.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-483485332745451 is a prime.

It is a super-2 number, since 2×4834853327454512 (a number of 30 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (483485332743451) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 345840723726 + ... + 345840725123.

It is an arithmetic number, because the mean of its divisors is an integer number (80926729515450).

Almost surely, 2483485332745451 is an apocalyptic number.

483485332745451 is a deficient number, since it is larger than the sum of its proper divisors (163928503378149).

483485332745451 is a wasteful number, since it uses less digits than its factorization.

483485332745451 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 691681449085.

The product of its digits is 774144000, while the sum is 66.

The spelling of 483485332745451 in words is "four hundred eighty-three trillion, four hundred eighty-five billion, three hundred thirty-two million, seven hundred forty-five thousand, four hundred fifty-one".

Divisors: 1 3 233 699 691681448849 2075044346547 161161777581817 483485332745451