Base | Representation |
---|---|
bin | 10101111111001000001011… |
… | …00010110111001111001101 |
3 | 20100012002000212120122101020 |
4 | 22333210011202313033031 |
5 | 22314120302202020201 |
6 | 250455002415304353 |
7 | 13120031614114650 |
oct | 1277440542671715 |
9 | 210162025518336 |
10 | 48348539876301 |
11 | 14450556353055 |
12 | 550a33021b0b9 |
13 | 20c932b3ba402 |
14 | bd2120707897 |
15 | 58c9ca916a36 |
hex | 2bf9058b73cd |
48348539876301 has 8 divisors (see below), whose sum is σ = 73673965525824. Its totient is φ = 27627737072160.
The previous prime is 48348539876237. The next prime is 48348539876303. The reversal of 48348539876301 is 10367893584384.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 48348539876301 - 26 = 48348539876237 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (48348539876303) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1151155711320 + ... + 1151155711361.
It is an arithmetic number, because the mean of its divisors is an integer number (9209245690728).
Almost surely, 248348539876301 is an apocalyptic number.
It is an amenable number.
48348539876301 is a deficient number, since it is larger than the sum of its proper divisors (25325425649523).
48348539876301 is a wasteful number, since it uses less digits than its factorization.
48348539876301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2302311422691.
The product of its (nonzero) digits is 418037760, while the sum is 69.
The spelling of 48348539876301 in words is "forty-eight trillion, three hundred forty-eight billion, five hundred thirty-nine million, eight hundred seventy-six thousand, three hundred one".
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