Base | Representation |
---|---|
bin | 100011001100010100000… |
… | …0010001101110111001001 |
3 | 122010101122020122021202020 |
4 | 1012120220002031313021 |
5 | 1113221234020020001 |
6 | 14141555241555053 |
7 | 1006306350555213 |
oct | 106305002156711 |
9 | 18111566567666 |
10 | 4836804845001 |
11 | 15a5306270138 |
12 | 6614a41a5a89 |
13 | 291154b941ac |
14 | 12a1617895b3 |
15 | 85c3a4e1736 |
hex | 4662808ddc9 |
4836804845001 has 16 divisors (see below), whose sum is σ = 6587972241408. Its totient is φ = 3155122106000.
The previous prime is 4836804844951. The next prime is 4836804845017. The reversal of 4836804845001 is 1005484086384.
It is a cyclic number.
It is not a de Polignac number, because 4836804845001 - 215 = 4836804812233 is a prime.
It is a super-2 number, since 2×48368048450012 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (4836804845701) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3834075 + ... + 4936976.
It is an arithmetic number, because the mean of its divisors is an integer number (411748265088).
Almost surely, 24836804845001 is an apocalyptic number.
It is an amenable number.
4836804845001 is a deficient number, since it is larger than the sum of its proper divisors (1751167396407).
4836804845001 is a wasteful number, since it uses less digits than its factorization.
4836804845001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8775012.
The product of its (nonzero) digits is 2949120, while the sum is 51.
The spelling of 4836804845001 in words is "four trillion, eight hundred thirty-six billion, eight hundred four million, eight hundred forty-five thousand, one".
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