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4836804845001 = 34739118771051
BaseRepresentation
bin100011001100010100000…
…0010001101110111001001
3122010101122020122021202020
41012120220002031313021
51113221234020020001
614141555241555053
71006306350555213
oct106305002156711
918111566567666
104836804845001
1115a5306270138
126614a41a5a89
13291154b941ac
1412a1617895b3
1585c3a4e1736
hex4662808ddc9

4836804845001 has 16 divisors (see below), whose sum is σ = 6587972241408. Its totient is φ = 3155122106000.

The previous prime is 4836804844951. The next prime is 4836804845017. The reversal of 4836804845001 is 1005484086384.

It is a cyclic number.

It is not a de Polignac number, because 4836804845001 - 215 = 4836804812233 is a prime.

It is a super-2 number, since 2×48368048450012 (a number of 26 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (4836804845701) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3834075 + ... + 4936976.

It is an arithmetic number, because the mean of its divisors is an integer number (411748265088).

Almost surely, 24836804845001 is an apocalyptic number.

It is an amenable number.

4836804845001 is a deficient number, since it is larger than the sum of its proper divisors (1751167396407).

4836804845001 is a wasteful number, since it uses less digits than its factorization.

4836804845001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8775012.

The product of its (nonzero) digits is 2949120, while the sum is 51.

The spelling of 4836804845001 in words is "four trillion, eight hundred thirty-six billion, eight hundred four million, eight hundred forty-five thousand, one".

Divisors: 1 3 47 141 3911 11733 183817 551451 8771051 26313153 412239397 1236718191 34303580461 102910741383 1612268281667 4836804845001