Base | Representation |
---|---|
bin | 10110000011101100000100… |
… | …00100100101011010110011 |
3 | 20100202001112010101202120120 |
4 | 23001312002010211122303 |
5 | 22324202221431214101 |
6 | 251055000412341323 |
7 | 13134250155342264 |
oct | 1301660204453263 |
9 | 210661463352516 |
10 | 48505247913651 |
11 | 14500a61a10a21 |
12 | 5534785474843 |
13 | 210b04362a129 |
14 | bd9948d3496b |
15 | 591aed38cb36 |
hex | 2c1d821256b3 |
48505247913651 has 32 divisors (see below), whose sum is σ = 68313252000000. Its totient is φ = 30528833758848.
The previous prime is 48505247913599. The next prime is 48505247913713. The reversal of 48505247913651 is 15631974250584.
It is not a de Polignac number, because 48505247913651 - 213 = 48505247905459 is a prime.
It is not an unprimeable number, because it can be changed into a prime (48505247913151) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 409098525 + ... + 409217073.
It is an arithmetic number, because the mean of its divisors is an integer number (2134789125000).
It is a 1-persistent number, because it is pandigital, but 2⋅48505247913651 = 97010495827302 is not.
Almost surely, 248505247913651 is an apocalyptic number.
48505247913651 is a deficient number, since it is larger than the sum of its proper divisors (19808004086349).
48505247913651 is a wasteful number, since it uses less digits than its factorization.
48505247913651 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 143363.
The product of its (nonzero) digits is 36288000, while the sum is 60.
The spelling of 48505247913651 in words is "forty-eight trillion, five hundred five billion, two hundred forty-seven million, nine hundred thirteen thousand, six hundred fifty-one".
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