Base | Representation |
---|---|
bin | 1110001000110001010… |
… | …10100011110000001001 |
3 | 1201102210102010110222021 |
4 | 13010120222203300021 |
5 | 30424301222122441 |
6 | 1011052003324441 |
7 | 50044134226321 |
oct | 7043052436011 |
9 | 1642712113867 |
10 | 485745114121 |
11 | 1780044a9783 |
12 | 7a183080721 |
13 | 36a61aa8667 |
14 | 1971dd5c281 |
15 | c97e4533d1 |
hex | 7118aa3c09 |
485745114121 has 4 divisors (see below), whose sum is σ = 485746675200. Its totient is φ = 485743553044.
The previous prime is 485745114089. The next prime is 485745114143. The reversal of 485745114121 is 121411547584.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 485745114121 - 25 = 485745114089 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (485745114191) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 136861 + ... + 995098.
It is an arithmetic number, because the mean of its divisors is an integer number (121436668800).
Almost surely, 2485745114121 is an apocalyptic number.
It is an amenable number.
485745114121 is a deficient number, since it is larger than the sum of its proper divisors (1561079).
485745114121 is a wasteful number, since it uses less digits than its factorization.
485745114121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1561078.
The product of its digits is 179200, while the sum is 43.
The spelling of 485745114121 in words is "four hundred eighty-five billion, seven hundred forty-five million, one hundred fourteen thousand, one hundred twenty-one".
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