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487661125333 = 17311675541037
BaseRepresentation
bin1110001100010101101…
…11100011111011010101
31201121201221102221020111
413012022313203323111
530442212222002313
61012010050203021
750142461112664
oct7061267437325
91647657387214
10487661125333
111788a7aa0318
127a618883471
1336ca8a26bc5
14198625d2ddb
15ca4277543d
hex718ade3ed5

487661125333 has 16 divisors (see below), whose sum is σ = 536195165184. Its totient is φ = 441509748480.

The previous prime is 487661125331. The next prime is 487661125351. The reversal of 487661125333 is 333521166784.

It is a cyclic number.

It is not a de Polignac number, because 487661125333 - 21 = 487661125331 is a prime.

It is a super-2 number, since 2×4876611253332 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (487661125331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2682510 + ... + 2858527.

It is an arithmetic number, because the mean of its divisors is an integer number (33512197824).

Almost surely, 2487661125333 is an apocalyptic number.

It is an amenable number.

487661125333 is a deficient number, since it is larger than the sum of its proper divisors (48534039851).

487661125333 is a wasteful number, since it uses less digits than its factorization.

487661125333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5541252.

The product of its digits is 2177280, while the sum is 49.

The spelling of 487661125333 in words is "four hundred eighty-seven billion, six hundred sixty-one million, one hundred twenty-five thousand, three hundred thirty-three".

Divisors: 1 17 31 167 527 2839 5177 88009 5541037 94197629 171772147 925353179 2920126499 15731004043 28685948549 487661125333