Base | Representation |
---|---|
bin | 100011011111110111001… |
… | …0111011011111001000011 |
3 | 122021102000001110211101001 |
4 | 1012333232113123321003 |
5 | 1114413223433030143 |
6 | 14213141145152431 |
7 | 1012323614164162 |
oct | 106775627337103 |
9 | 18242001424331 |
10 | 4878787001923 |
11 | 161109a088a9a |
12 | 66965ba8b717 |
13 | 2950b57b4373 |
14 | 12c1c52c93d9 |
15 | 86d9601414d |
hex | 46fee5dbe43 |
4878787001923 has 4 divisors (see below), whose sum is σ = 4878792544968. Its totient is φ = 4878781458880.
The previous prime is 4878787001801. The next prime is 4878787001941. The reversal of 4878787001923 is 3291007878784.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 4878787001923 - 29 = 4878787001411 is a prime.
It is a super-2 number, since 2×48787870019232 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4878787001983) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1125361 + ... + 3320242.
It is an arithmetic number, because the mean of its divisors is an integer number (1219698136242).
Almost surely, 24878787001923 is an apocalyptic number.
4878787001923 is a deficient number, since it is larger than the sum of its proper divisors (5543045).
4878787001923 is a wasteful number, since it uses less digits than its factorization.
4878787001923 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5543044.
The product of its (nonzero) digits is 37933056, while the sum is 64.
The spelling of 4878787001923 in words is "four trillion, eight hundred seventy-eight billion, seven hundred eighty-seven million, one thousand, nine hundred twenty-three".
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