Base | Representation |
---|---|
bin | 10110010010100010001000… |
… | …11110001100110110110101 |
3 | 20102112211002121122101001101 |
4 | 23021101010132030312311 |
5 | 22411031331240041441 |
6 | 252125154120130101 |
7 | 13216145132613211 |
oct | 1311210436146665 |
9 | 212484077571041 |
10 | 49015315549621 |
11 | 1468830788a323 |
12 | 55b75b6006931 |
13 | 2147180486b45 |
14 | c164d5285941 |
15 | 5a0002c8e231 |
hex | 2c944478cdb5 |
49015315549621 has 4 divisors (see below), whose sum is σ = 49015702150272. Its totient is φ = 49014928948972.
The previous prime is 49015315549619. The next prime is 49015315549643. The reversal of 49015315549621 is 12694551351094.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 49015315549621 - 21 = 49015315549619 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (49015315559621) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 193110085 + ... + 193363738.
It is an arithmetic number, because the mean of its divisors is an integer number (12253925537568).
Almost surely, 249015315549621 is an apocalyptic number.
It is an amenable number.
49015315549621 is a deficient number, since it is larger than the sum of its proper divisors (386600651).
49015315549621 is a wasteful number, since it uses less digits than its factorization.
49015315549621 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 386600650.
The product of its (nonzero) digits is 5832000, while the sum is 55.
The spelling of 49015315549621 in words is "forty-nine trillion, fifteen billion, three hundred fifteen million, five hundred forty-nine thousand, six hundred twenty-one".
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