Base | Representation |
---|---|
bin | 100011101011101011111… |
… | …1110100110011000110101 |
3 | 122100211112211010120021020 |
4 | 1013113113332212120311 |
5 | 1120322230341240331 |
6 | 14232541051011353 |
7 | 1014213116240340 |
oct | 107272776463065 |
9 | 18324484116236 |
10 | 4904181196341 |
11 | 1620940485129 |
12 | 672568439b59 |
13 | 2976018a87cb |
14 | 12d513b65457 |
15 | 878805eec96 |
hex | 475d7fa6635 |
4904181196341 has 8 divisors (see below), whose sum is σ = 7473038013504. Its totient is φ = 2802389255040.
The previous prime is 4904181196261. The next prime is 4904181196357. The reversal of 4904181196341 is 1436911814094.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 4904181196341 - 215 = 4904181163573 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4904181196241) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 116766218940 + ... + 116766218981.
It is an arithmetic number, because the mean of its divisors is an integer number (934129751688).
Almost surely, 24904181196341 is an apocalyptic number.
It is an amenable number.
4904181196341 is a deficient number, since it is larger than the sum of its proper divisors (2568856817163).
4904181196341 is a wasteful number, since it uses less digits than its factorization.
4904181196341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 233532437931.
The product of its (nonzero) digits is 746496, while the sum is 51.
The spelling of 4904181196341 in words is "four trillion, nine hundred four billion, one hundred eighty-one million, one hundred ninety-six thousand, three hundred forty-one".
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