Base | Representation |
---|---|
bin | 101101101011011010… |
… | …101101001000000011 |
3 | 11200121011012202002022 |
4 | 231223122231020003 |
5 | 1300421440143242 |
6 | 34310511112055 |
7 | 3354265642412 |
oct | 555332551003 |
9 | 150534182068 |
10 | 49046802947 |
11 | 19889706a9a |
12 | 960981262b |
13 | 481843b9bc |
14 | 2533cc7479 |
15 | 1420d5b0d2 |
hex | b6b6ad203 |
49046802947 has 4 divisors (see below), whose sum is σ = 49049352216. Its totient is φ = 49044253680.
The previous prime is 49046802929. The next prime is 49046803021. The reversal of 49046802947 is 74920864094.
49046802947 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 49046802947 - 212 = 49046798851 is a prime.
It is a super-3 number, since 3×490468029473 (a number of 33 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (49046802907) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1245554 + ... + 1284327.
It is an arithmetic number, because the mean of its divisors is an integer number (12262338054).
Almost surely, 249046802947 is an apocalyptic number.
49046802947 is a deficient number, since it is larger than the sum of its proper divisors (2549269).
49046802947 is a wasteful number, since it uses less digits than its factorization.
49046802947 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2549268.
The product of its (nonzero) digits is 3483648, while the sum is 53.
The spelling of 49046802947 in words is "forty-nine billion, forty-six million, eight hundred two thousand, nine hundred forty-seven".
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