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49050066404263 = 291691381600147
BaseRepresentation
bin10110010011100010110111…
…10010001100001110100111
320102200010210110111200210211
423021301123302030032213
522412114013444414023
6252153142303400251
713221515241164221
oct1311613362141647
9212603713450724
1049050066404263
11146a101a830801
125602293bb3087
13214a52aba7122
14c18070659411
155a0d88a08a0d
hex2c9c5bc8c3a7

49050066404263 has 4 divisors (see below), whose sum is σ = 50741448004440. Its totient is φ = 47358684804088.

The previous prime is 49050066404257. The next prime is 49050066404267. The reversal of 49050066404263 is 36240466005094.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-49050066404263 is a prime.

It is a super-2 number, since 2×490500664042632 (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (49050066404267) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 845690800045 + ... + 845690800102.

It is an arithmetic number, because the mean of its divisors is an integer number (12685362001110).

Almost surely, 249050066404263 is an apocalyptic number.

49050066404263 is a deficient number, since it is larger than the sum of its proper divisors (1691381600177).

49050066404263 is a wasteful number, since it uses less digits than its factorization.

49050066404263 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1691381600176.

The product of its (nonzero) digits is 3732480, while the sum is 49.

The spelling of 49050066404263 in words is "forty-nine trillion, fifty billion, sixty-six million, four hundred four thousand, two hundred sixty-three".

Divisors: 1 29 1691381600147 49050066404263