Base | Representation |
---|---|
bin | 101101101100011010… |
… | …110100010111011001 |
3 | 11200122022211121202222 |
4 | 231230122310113121 |
5 | 1300440241003232 |
6 | 34312311233425 |
7 | 3354561542135 |
oct | 555432642731 |
9 | 150568747688 |
10 | 49063609817 |
11 | 19898146272 |
12 | 9613378875 |
13 | 481ba748b1 |
14 | 25362203c5 |
15 | 142257ad12 |
hex | b6c6b45d9 |
49063609817 has 4 divisors (see below), whose sum is σ = 49064780196. Its totient is φ = 49062439440.
The previous prime is 49063609757. The next prime is 49063609823. The reversal of 49063609817 is 71890636094.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 8953133641 + 40110476176 = 94621^2 + 200276^2 .
It is a cyclic number.
It is not a de Polignac number, because 49063609817 - 26 = 49063609753 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (49063609117) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 519878 + ... + 606959.
It is an arithmetic number, because the mean of its divisors is an integer number (12266195049).
Almost surely, 249063609817 is an apocalyptic number.
It is an amenable number.
49063609817 is a deficient number, since it is larger than the sum of its proper divisors (1170379).
49063609817 is a wasteful number, since it uses less digits than its factorization.
49063609817 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1170378.
The product of its (nonzero) digits is 1959552, while the sum is 53.
The spelling of 49063609817 in words is "forty-nine billion, sixty-three million, six hundred nine thousand, eight hundred seventeen".
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