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4908051246391 = 21123260906381
BaseRepresentation
bin100011101101011111010…
…1001101010110100110111
3122101012112112022110220021
41013122332221222310313
51120403142104341031
614234421055350011
71014411041152156
oct107327651526467
918335475273807
104908051246391
111622546a80aa7
12673268522307
13297a9a5cb457
1412d79db2d59d
1587a0a256511
hex476bea6ad37

4908051246391 has 4 divisors (see below), whose sum is σ = 4931312152984. Its totient is φ = 4884790339800.

The previous prime is 4908051246367. The next prime is 4908051246431. The reversal of 4908051246391 is 1936421508094.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4908051246391 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4908051246311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11630452980 + ... + 11630453401.

It is an arithmetic number, because the mean of its divisors is an integer number (1232828038246).

Almost surely, 24908051246391 is an apocalyptic number.

4908051246391 is a deficient number, since it is larger than the sum of its proper divisors (23260906593).

4908051246391 is a wasteful number, since it uses less digits than its factorization.

4908051246391 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23260906592.

The product of its (nonzero) digits is 1866240, while the sum is 52.

The spelling of 4908051246391 in words is "four trillion, nine hundred eight billion, fifty-one million, two hundred forty-six thousand, three hundred ninety-one".

Divisors: 1 211 23260906381 4908051246391