Base | Representation |
---|---|
bin | 101101101110110011… |
… | …010011101000010011 |
3 | 11200202010001111201111 |
4 | 231232303103220103 |
5 | 1301031004140023 |
6 | 34320300114151 |
7 | 3355555401223 |
oct | 555663235023 |
9 | 150663044644 |
10 | 49103583763 |
11 | 19908769293 |
12 | 9624835957 |
13 | 482712c610 |
14 | 253b668083 |
15 | 1425d2500d |
hex | b6ecd3a13 |
49103583763 has 32 divisors (see below), whose sum is σ = 55796428800. Its totient is φ = 42900278400.
The previous prime is 49103583731. The next prime is 49103583791. The reversal of 49103583763 is 36738530194.
It is a cyclic number.
It is not a de Polignac number, because 49103583763 - 25 = 49103583731 is a prime.
It is a super-2 number, since 2×491035837632 (a number of 22 digits) contains 22 as substring.
It is a Smith number, since the sum of its digits (49) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.
It is not an unprimeable number, because it can be changed into a prime (49103583713) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4394778 + ... + 4405936.
It is an arithmetic number, because the mean of its divisors is an integer number (1743638400).
Almost surely, 249103583763 is an apocalyptic number.
49103583763 is a deficient number, since it is larger than the sum of its proper divisors (6692845037).
49103583763 is a wasteful number, since it uses less digits than its factorization.
49103583763 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11443.
The product of its (nonzero) digits is 1632960, while the sum is 49.
The spelling of 49103583763 in words is "forty-nine billion, one hundred three million, five hundred eighty-three thousand, seven hundred sixty-three".
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