491325403 has 4 divisors (see below), whose sum is σ = 492268968. Its totient is φ = 490381840.

The previous prime is 491325361. The next prime is 491325421. The reversal of 491325403 is 304523194.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 304523194 = 2 ⋅152261597.

It is a cyclic number.

It is not a de Polignac number, because 491325403 - 2²¹ = 489228251 is a prime.

It is a super-2 number, since 2×491325403² = 482801303266224818, which contains 22 as substring.

It is a Smith number, since the sum of its digits (31) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (491325463) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 471001 + ... + 472042.

It is an arithmetic number, because the mean of its divisors is an integer number (123067242).

Almost surely, 2^491325403 is an apocalyptic number.

491325403 is a deficient number, since it is larger than the sum of its proper divisors (943565).

491325403 is an equidigital number, since it uses as much as digits as its factorization.

491325403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 943564.

The product of its (nonzero) digits is 12960, while the sum is 31.

The square root of 491325403 is about 22165.8612059175. The cubic root of 491325403 is about 789.0837012815.

Adding to 491325403 its reverse (304523194), we get a palindrome (795848597).

The spelling of 491325403 in words is "four hundred ninety-one million, three hundred twenty-five thousand, four hundred three".