4913972659909 has 4 divisors (see below), whose sum is σ = 4926938287360. Its totient is φ = 4901007032460.

The previous prime is 4913972659903. The next prime is 4913972659931. The reversal of 4913972659909 is 9099562793194.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4913972659909 - 2⁵ = 4913972659877 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4913972659903) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6482813157 + ... + 6482813914.

It is an arithmetic number, because the mean of its divisors is an integer number (1231734571840).

Almost surely, 2^{4913972659909} is an apocalyptic number.

It is an amenable number.

4913972659909 is a deficient number, since it is larger than the sum of its proper divisors (12965627451).

4913972659909 is a wasteful number, since it uses less digits than its factorization.

4913972659909 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12965627450.

The product of its (nonzero) digits is 297606960, while the sum is 73.

The spelling of 4913972659909 in words is "four trillion, nine hundred thirteen billion, nine hundred seventy-two million, six hundred fifty-nine thousand, nine hundred nine".