Base | Representation |
---|---|
bin | 101101110010111011… |
… | …010100111000111111 |
3 | 11200220221021210121112 |
4 | 231302323110320333 |
5 | 1301201213414233 |
6 | 34331211352235 |
7 | 3360355601126 |
oct | 556273247077 |
9 | 150827253545 |
10 | 49172794943 |
11 | 19943840708 |
12 | 9643a5267b |
13 | 483858308c |
14 | 2546922abd |
15 | 142be47048 |
hex | b72ed4e3f |
49172794943 has 4 divisors (see below), whose sum is σ = 49261077000. Its totient is φ = 49084512888.
The previous prime is 49172794939. The next prime is 49172794987. The reversal of 49172794943 is 34949727194.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 49172794943 - 22 = 49172794939 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (49172794343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 44140193 + ... + 44141306.
It is an arithmetic number, because the mean of its divisors is an integer number (12315269250).
Almost surely, 249172794943 is an apocalyptic number.
49172794943 is a deficient number, since it is larger than the sum of its proper divisors (88282057).
49172794943 is an equidigital number, since it uses as much as digits as its factorization.
49172794943 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 88282056.
The product of its digits is 13716864, while the sum is 59.
The spelling of 49172794943 in words is "forty-nine billion, one hundred seventy-two million, seven hundred ninety-four thousand, nine hundred forty-three".
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