Base | Representation |
---|---|
bin | 1110010100011110111… |
… | …10110101110100011101 |
3 | 1202001000122211111111121 |
4 | 13022033132311310131 |
5 | 31030141033422042 |
6 | 1014012001250541 |
7 | 50356022505220 |
oct | 7121736656435 |
9 | 1661018744447 |
10 | 492033498397 |
11 | 17a74109a981 |
12 | 7b439033a51 |
13 | 375248360bc |
14 | 19b591995b7 |
15 | cbeb553367 |
hex | 728f7b5d1d |
492033498397 has 4 divisors (see below), whose sum is σ = 562323998176. Its totient is φ = 421742998620.
The previous prime is 492033498301. The next prime is 492033498431. The reversal of 492033498397 is 793894330294.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 492033498397 - 235 = 457673760029 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (492033498197) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35145249879 + ... + 35145249892.
It is an arithmetic number, because the mean of its divisors is an integer number (140580999544).
Almost surely, 2492033498397 is an apocalyptic number.
It is an amenable number.
492033498397 is a deficient number, since it is larger than the sum of its proper divisors (70290499779).
492033498397 is an equidigital number, since it uses as much as digits as its factorization.
492033498397 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 70290499778.
The product of its (nonzero) digits is 35271936, while the sum is 61.
The spelling of 492033498397 in words is "four hundred ninety-two billion, thirty-three million, four hundred ninety-eight thousand, three hundred ninety-seven".
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