Base | Representation |
---|---|
bin | 1110010101000010111… |
… | …01110101100101110001 |
3 | 1202001210200120210212102 |
4 | 13022201131311211301 |
5 | 31031300304201301 |
6 | 1014101540310145 |
7 | 50366345236211 |
oct | 7124135654561 |
9 | 1661720523772 |
10 | 492335225201 |
11 | 17a886443776 |
12 | 7b5020a2355 |
13 | 375721b9b81 |
14 | 19b8729c241 |
15 | cc17ca3b6b |
hex | 72a1775971 |
492335225201 has 4 divisors (see below), whose sum is σ = 492576686400. Its totient is φ = 492093764004.
The previous prime is 492335225191. The next prime is 492335225231. The reversal of 492335225201 is 102522533294.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 492335225201 - 210 = 492335224177 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (492335225231) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 120727541 + ... + 120731618.
It is an arithmetic number, because the mean of its divisors is an integer number (123144171600).
Almost surely, 2492335225201 is an apocalyptic number.
It is an amenable number.
492335225201 is a deficient number, since it is larger than the sum of its proper divisors (241461199).
492335225201 is a wasteful number, since it uses less digits than its factorization.
492335225201 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 241461198.
The product of its (nonzero) digits is 129600, while the sum is 38.
Adding to 492335225201 its reverse (102522533294), we get a palindrome (594857758495).
The spelling of 492335225201 in words is "four hundred ninety-two billion, three hundred thirty-five million, two hundred twenty-five thousand, two hundred one".
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