Base | Representation |
---|---|
bin | 101101110111010000… |
… | …011110001101100101 |
3 | 11201002222222220111221 |
4 | 231313100132031211 |
5 | 1301323313301023 |
6 | 34342324500341 |
7 | 3362230251550 |
oct | 556720361545 |
9 | 151088886457 |
10 | 49245447013 |
11 | 19980853244 |
12 | 966424a6b1 |
13 | 484a63ca79 |
14 | 2552435697 |
15 | 14334e885d |
hex | b7741e365 |
49245447013 has 4 divisors (see below), whose sum is σ = 56280510880. Its totient is φ = 42210383148.
The previous prime is 49245447011. The next prime is 49245447029. The reversal of 49245447013 is 31074454294.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 49245447013 - 21 = 49245447011 is a prime.
It is a super-2 number, since 2×492454470132 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (49245447011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3517531923 + ... + 3517531936.
It is an arithmetic number, because the mean of its divisors is an integer number (14070127720).
Almost surely, 249245447013 is an apocalyptic number.
It is an amenable number.
49245447013 is a deficient number, since it is larger than the sum of its proper divisors (7035063867).
49245447013 is an equidigital number, since it uses as much as digits as its factorization.
49245447013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7035063866.
The product of its (nonzero) digits is 483840, while the sum is 43.
The spelling of 49245447013 in words is "forty-nine billion, two hundred forty-five million, four hundred forty-seven thousand, thirteen".
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