4926179113 has 4 divisors (see below), whose sum is σ = 4926325588. Its totient is φ = 4926032640.

The previous prime is 4926179101. The next prime is 4926179117. The reversal of 4926179113 is 3119716294.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 3119716294 = 2 ⋅1559858147.

It can be written as a sum of positive squares in 2 ways, for example, as 1660399504 + 3265779609 = 40748^2 + 57147^2 .

It is a cyclic number.

It is not a de Polignac number, because 4926179113 - 2¹⁷ = 4926048041 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 4926179113.

It is not an unprimeable number, because it can be changed into a prime (4926179117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5245 + ... + 99397.

It is an arithmetic number, because the mean of its divisors is an integer number (1231581397).

Almost surely, 2^4926179113 is an apocalyptic number.

It is an amenable number.

4926179113 is a deficient number, since it is larger than the sum of its proper divisors (146475).

4926179113 is an equidigital number, since it uses as much as digits as its factorization.

4926179113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 146474.

The product of its digits is 81648, while the sum is 43.

The square root of 4926179113 is about 70186.7445676176. The cubic root of 4926179113 is about 1701.5187250537.

The spelling of 4926179113 in words is "four billion, nine hundred twenty-six million, one hundred seventy-nine thousand, one hundred thirteen".