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49311396397 = 672105934949
BaseRepresentation
bin101101111011001100…
…000011001000101101
311201021121002111001201
4231323030003020231
51301442204141042
634353042205501
73363660645034
oct557314031055
9151247074051
1049311396397
1119a04aa7a6a
129682353891
13485b1c0983
14255b0c171b
1514391c41b7
hexb7b30322d

49311396397 has 8 divisors (see below), whose sum is σ = 50051196000. Its totient is φ = 48571708944.

The previous prime is 49311396353. The next prime is 49311396419. The reversal of 49311396397 is 79369311394.

49311396397 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 49311396397 - 219 = 49310872109 is a prime.

It is a super-2 number, since 2×493113963972 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (49311394397) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1393479 + ... + 1428427.

It is an arithmetic number, because the mean of its divisors is an integer number (6256399500).

Almost surely, 249311396397 is an apocalyptic number.

It is an amenable number.

49311396397 is a deficient number, since it is larger than the sum of its proper divisors (739799603).

49311396397 is a wasteful number, since it uses less digits than its factorization.

49311396397 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 56075.

The product of its digits is 3306744, while the sum is 55.

The spelling of 49311396397 in words is "forty-nine billion, three hundred eleven million, three hundred ninety-six thousand, three hundred ninety-seven".

Divisors: 1 67 21059 34949 1410953 2341583 735990991 49311396397