Base | Representation |
---|---|
bin | 1110010110111001100… |
… | …00101110101011110011 |
3 | 1202011101000111022011100 |
4 | 13023130300232223303 |
5 | 31040314442032040 |
6 | 1014344354415443 |
7 | 50433115044513 |
oct | 7133460565363 |
9 | 1664330438140 |
10 | 493330033395 |
11 | 180246a40901 |
12 | 7b73b291583 |
13 | 376a0329b84 |
14 | 19c3d457843 |
15 | cc752abb30 |
hex | 72dcc2eaf3 |
493330033395 has 48 divisors (see below), whose sum is σ = 887566627584. Its totient is φ = 253215072000.
The previous prime is 493330033379. The next prime is 493330033397. The reversal of 493330033395 is 593330033394.
493330033395 is a `hidden beast` number, since 4 + 9 + 3 + 3 + 300 + 3 + 339 + 5 = 666.
It is not a de Polignac number, because 493330033395 - 24 = 493330033379 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (45).
It is a self number, because there is not a number n which added to its sum of digits gives 493330033395.
It is not an unprimeable number, because it can be changed into a prime (493330033397) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 724416 + ... + 1229405.
It is an arithmetic number, because the mean of its divisors is an integer number (18490971408).
Almost surely, 2493330033395 is an apocalyptic number.
493330033395 is a gapful number since it is divisible by the number (45) formed by its first and last digit.
493330033395 is a deficient number, since it is larger than the sum of its proper divisors (394236594189).
493330033395 is a wasteful number, since it uses less digits than its factorization.
493330033395 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1954044 (or 1954041 counting only the distinct ones).
The product of its (nonzero) digits is 1180980, while the sum is 45.
Subtracting 493330033395 from its reverse (593330033394), we obtain a palindrome (99999999999).
The spelling of 493330033395 in words is "four hundred ninety-three billion, three hundred thirty million, thirty-three thousand, three hundred ninety-five".
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