Base | Representation |
---|---|
bin | 1110010111001010000… |
… | …01000001010011010001 |
3 | 1202011201200002020101010 |
4 | 13023211001001103101 |
5 | 31041110420143211 |
6 | 1014410223001133 |
7 | 50436416140452 |
oct | 7134501012321 |
9 | 1664650066333 |
10 | 493468521681 |
11 | 180308130133 |
12 | 7b7797391a9 |
13 | 376c2c280c5 |
14 | 19c539c7129 |
15 | cc825154a6 |
hex | 72e50414d1 |
493468521681 has 4 divisors (see below), whose sum is σ = 657958028912. Its totient is φ = 328979014452.
The previous prime is 493468521673. The next prime is 493468521713. The reversal of 493468521681 is 186125864394.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 493468521681 - 23 = 493468521673 is a prime.
It is a super-2 number, since 2×4934685216812 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (493468525681) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 82244753611 + ... + 82244753616.
It is an arithmetic number, because the mean of its divisors is an integer number (164489507228).
Almost surely, 2493468521681 is an apocalyptic number.
It is an amenable number.
493468521681 is a deficient number, since it is larger than the sum of its proper divisors (164489507231).
493468521681 is a wasteful number, since it uses less digits than its factorization.
493468521681 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 164489507230.
The product of its digits is 9953280, while the sum is 57.
The spelling of 493468521681 in words is "four hundred ninety-three billion, four hundred sixty-eight million, five hundred twenty-one thousand, six hundred eighty-one".
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