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493468521713 is a prime number
BaseRepresentation
bin1110010111001010000…
…01000001010011110001
31202011201200002020102022
413023211001001103301
531041110420143323
61014410223001225
750436416140526
oct7134501012361
91664650066368
10493468521713
11180308130162
127b779739215
13376c2c2811b
1419c539c714d
15cc825154c8
hex72e50414f1

493468521713 has 2 divisors, whose sum is σ = 493468521714. Its totient is φ = 493468521712.

The previous prime is 493468521673. The next prime is 493468521761. The reversal of 493468521713 is 317125864394.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 405097879729 + 88370641984 = 636473^2 + 297272^2 .

It is a cyclic number.

It is not a de Polignac number, because 493468521713 - 234 = 476288652529 is a prime.

It is a super-2 number, since 2×4934685217132 (a number of 24 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (493468581713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 246734260856 + 246734260857.

It is an arithmetic number, because the mean of its divisors is an integer number (246734260857).

Almost surely, 2493468521713 is an apocalyptic number.

It is an amenable number.

493468521713 is a deficient number, since it is larger than the sum of its proper divisors (1).

493468521713 is an equidigital number, since it uses as much as digits as its factorization.

493468521713 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4354560, while the sum is 53.

The spelling of 493468521713 in words is "four hundred ninety-three billion, four hundred sixty-eight million, five hundred twenty-one thousand, seven hundred thirteen".