Base | Representation |
---|---|
bin | 101101111101010100… |
… | …010110110101011001 |
3 | 11201101002022212112001 |
4 | 231331110112311121 |
5 | 1302030331104130 |
6 | 34400400121001 |
7 | 3364603446532 |
oct | 557524266531 |
9 | 151332285461 |
10 | 49347128665 |
11 | 19a2319316a |
12 | 9692306161 |
13 | 4865721b23 |
14 | 2561b43689 |
15 | 143c3d16ca |
hex | b7d516d59 |
49347128665 has 4 divisors (see below), whose sum is σ = 59216554404. Its totient is φ = 39477702928.
The previous prime is 49347128653. The next prime is 49347128669. The reversal of 49347128665 is 56682174394.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 56682174394 = 2 ⋅28341087197.
It can be written as a sum of positive squares in 2 ways, for example, as 6333613056 + 43013515609 = 79584^2 + 207397^2 .
It is a cyclic number.
It is not a de Polignac number, because 49347128665 - 211 = 49347126617 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (49347128669) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4934712862 + ... + 4934712871.
It is an arithmetic number, because the mean of its divisors is an integer number (14804138601).
Almost surely, 249347128665 is an apocalyptic number.
It is an amenable number.
49347128665 is a deficient number, since it is larger than the sum of its proper divisors (9869425739).
49347128665 is an equidigital number, since it uses as much as digits as its factorization.
49347128665 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9869425738.
The product of its digits is 8709120, while the sum is 55.
The spelling of 49347128665 in words is "forty-nine billion, three hundred forty-seven million, one hundred twenty-eight thousand, six hundred sixty-five".
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