4935312135394 has 4 divisors (see below), whose sum is σ = 7402968203094. Its totient is φ = 2467656067696.

The previous prime is 4935312135373. The next prime is 4935312135409.

4935312135394 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 3873870286225 + 1061441849169 = 1968215^2 + 1030263^2 .

It is a super-3 number, since 3×4935312135394³ (a number of 39 digits) contains 333 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1233828033847 + ... + 1233828033850.

Almost surely, 2^{4935312135394} is an apocalyptic number.

4935312135394 is a deficient number, since it is larger than the sum of its proper divisors (2467656067700).

4935312135394 is a wasteful number, since it uses less digits than its factorization.

4935312135394 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2467656067699.

The product of its digits is 5248800, while the sum is 52.

The spelling of 4935312135394 in words is "four trillion, nine hundred thirty-five billion, three hundred twelve million, one hundred thirty-five thousand, three hundred ninety-four".