Base | Representation |
---|---|
bin | 100011111100000000110… |
… | …0101100110001011100111 |
3 | 122111012001001121200221001 |
4 | 1013320001211212023213 |
5 | 1121411030142221320 |
6 | 14301015521534131 |
7 | 1016563642660441 |
oct | 107700145461347 |
9 | 18435031550831 |
10 | 4939239023335 |
11 | 16347a0732471 |
12 | 6793111a4347 |
13 | 29a9caa98336 |
14 | 1310bbc05491 |
15 | 887332a420a |
hex | 47e019662e7 |
4939239023335 has 4 divisors (see below), whose sum is σ = 5927086828008. Its totient is φ = 3951391218664.
The previous prime is 4939239023333. The next prime is 4939239023339. The reversal of 4939239023335 is 5333209329394.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4939239023335 - 21 = 4939239023333 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4939239023333) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 493923902329 + ... + 493923902338.
It is an arithmetic number, because the mean of its divisors is an integer number (1481771707002).
Almost surely, 24939239023335 is an apocalyptic number.
4939239023335 is a deficient number, since it is larger than the sum of its proper divisors (987847804673).
4939239023335 is an equidigital number, since it uses as much as digits as its factorization.
4939239023335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 987847804672.
The product of its (nonzero) digits is 14171760, while the sum is 55.
The spelling of 4939239023335 in words is "four trillion, nine hundred thirty-nine billion, two hundred thirty-nine million, twenty-three thousand, three hundred thirty-five".
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