Base | Representation |
---|---|
bin | 100011111100100111010… |
… | …1001110010100100100011 |
3 | 122111022101011112002222021 |
4 | 1013321032221302210203 |
5 | 1121421202140441131 |
6 | 14301352110122311 |
7 | 1016640662555323 |
oct | 107711651624443 |
9 | 18438334462867 |
10 | 4940531968291 |
11 | 16352a4551117 |
12 | 6796121b0397 |
13 | 29ab7590301a |
14 | 1311a180b283 |
15 | 887aba4de11 |
hex | 47e4ea72923 |
4940531968291 has 8 divisors (see below), whose sum is σ = 5045705421120. Its totient is φ = 4835360838528.
The previous prime is 4940531968243. The next prime is 4940531968301. The reversal of 4940531968291 is 1928691350494.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 4940531968291 - 213 = 4940531960099 is a prime.
It is a super-2 number, since 2×49405319682912 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4940531960291) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4118385 + ... + 5180941.
It is an arithmetic number, because the mean of its divisors is an integer number (630713177640).
Almost surely, 24940531968291 is an apocalyptic number.
4940531968291 is a deficient number, since it is larger than the sum of its proper divisors (105173452829).
4940531968291 is a wasteful number, since it uses less digits than its factorization.
4940531968291 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1161533.
The product of its (nonzero) digits is 16796160, while the sum is 61.
The spelling of 4940531968291 in words is "four trillion, nine hundred forty billion, five hundred thirty-one million, nine hundred sixty-eight thousand, two hundred ninety-one".
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