Base | Representation |
---|---|
bin | 101110000010001011… |
… | …101001100111010011 |
3 | 11201120202212202202112 |
4 | 232002023221213103 |
5 | 1302212223413441 |
6 | 34412433135535 |
7 | 3366614202314 |
oct | 560213514723 |
9 | 151522782675 |
10 | 49428732371 |
11 | 19a6525a247 |
12 | 96b56ba5ab |
13 | 48795c4145 |
14 | 256c90660b |
15 | 14446504eb |
hex | b822e99d3 |
49428732371 has 4 divisors (see below), whose sum is σ = 49435513512. Its totient is φ = 49421951232.
The previous prime is 49428732341. The next prime is 49428732377. The reversal of 49428732371 is 17323782494.
It is a happy number.
49428732371 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 49428732371 - 222 = 49424538067 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (49428732377) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3379625 + ... + 3394218.
It is an arithmetic number, because the mean of its divisors is an integer number (12358878378).
Almost surely, 249428732371 is an apocalyptic number.
49428732371 is a deficient number, since it is larger than the sum of its proper divisors (6781141).
49428732371 is an equidigital number, since it uses as much as digits as its factorization.
49428732371 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6781140.
The product of its digits is 2032128, while the sum is 50.
The spelling of 49428732371 in words is "forty-nine billion, four hundred twenty-eight million, seven hundred thirty-two thousand, three hundred seventy-one".
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